A definite integral that defines a constant, and solving it by iteration
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The teaching part (1 min) is free to watch. A free account opens the whole lecture: 6 practice questions, 1 real past-paper question with the answer explained, the mistakes that lose marks, the full-marks tip, a one-card summary and a quick quiz.
What this lecture covers
- The constant hides in the limit
- Plan of attack
- Integration by parts
Read the transcript of the teaching part
Last time
Before we start: last time, in Iteration, you learned these points. Here they are again on one card. Keep them in mind, because today builds on them.
The constant hides in the limit
Here is a question type that chains three skills together. A definite integral from zero to a is given as a number. Integrate by parts, and you get an equation that a satisfies. But that equation has a on both sides, with an exponential, so you cannot solve it directly. Show the root lies in an interval, then iterate.
Plan of attack
Part one: integrate by parts, apply the limits, and rearrange to a given equation. The answer is printed, so every line counts. Part two: verify that a lies between two values by evaluating the equation's difference at both and spotting a sign change. Part three: iterate the formula until two successive values agree to the required accuracy.
Integration by parts
Let u equal x and v prime equal e to the minus 2x. Then u prime is 1 and v is minus a half e to the minus 2x. The integral of x e to the minus 2x is minus x e to the minus 2x over 2, plus a half of the integral of e to the minus 2x. Finish: minus a half x e to the minus 2x, minus a quarter e to the minus 2x.
Chapter 3.6: Numerical solution of equations
- Iteration: locating roots and using iterative formulas 7 min
- A definite integral that defines a constant, and solving it by iteration 6 min
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