ExamYard Lectures

Concentration and titration calculations

IGCSE Chemistry 0620 · Chapter 3, Stoichiometry · 9-minute lecture

The teaching part (1 min) is free to watch. A free account opens the whole lecture: 6 worked examples, 6 practice questions, 2 real past-paper questions with the answers explained, the mistakes that lose marks, the full-marks tip, a one-card summary and a quick quiz.

What this lecture covers

  1. Strong or weak squash?
  2. Concentration
  3. The formulae
Read the transcript of the teaching part

Last time

Before we start: last time, in Moles, you learned these points. Here they are again on one card. Keep them in mind, because today builds on them.

Strong or weak squash?

Two glasses of orange squash can look the same size, but one tastes much stronger. The strong one has more squash dissolved in the same volume of water. In chemistry, that idea is called concentration, and a titration is the way to measure it exactly.

Concentration

The concentration of a solution is the amount of solute dissolved in one decimetre cubed of solution. It is measured in moles per decimetre cubed, written mol per dm³, or in grams per decimetre cubed. Convert the volume to dm³ first. A cubic centimetre is one thousandth of a dm³, so divide by one thousand.

The formulae

Concentration in mol per dm³ equals moles divided by volume in dm³. So the moles equal the concentration times the volume in dm³. To change mol per dm³ into g per dm³, multiply by the Mr.

How often it comes up

How often Cambridge has asked each part, counted by ExamYard from every past paper in its question bank: Moles: titration calculations · Concentration.

The whole chapter: Stoichiometry, Stoichiometry.

Chapter 3: Stoichiometry

Also for IGCSE Chemistry 0620

Which topics come up most in IGCSE Chemistry 0620 past papers, counted from every paper since 2004.